Day 6: Strings - 30 Days Code - IndianTechnoEra
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Day 6: Strings - 30 Days Code

Introduction:

Welcome to Day 6 of the 30 Days of Code challenge! Today, we'll explore the combination of strings and loops to manipulate and print characters at even and odd indices. Understanding string manipulation is a crucial skill in programming, and this challenge will help reinforce your knowledge.


The Challenge:

Given a string, s, of length n, we are tasked with printing its even-indexed and odd-indexed characters as space-separated strings on a single line. In this context, indices are considered even when they are divisible by 2.


Format & Sample:

For example, if we have the string "Hacker," the output should be "Hce akr." The even-indexed characters are 'H,' 'c,' and 'r,' while the odd-indexed characters are 'a,' 'k,' and 'e.'

Input Format:

The first line contains an integer, t (the number of test cases).

Each of the t subsequent lines contains a string, s.


Output Format:

For each string s (where 1 <= i <= t), print 's even-indexed characters, followed by a space, followed by 's odd-indexed characters.


Sample Input:

2

Hacker

Rank


Sample Output:

Hce akr

Rn ak


Explanation:

Test Case 0: The even indices are 0, 2, and 4, while the odd indices are 1, 3, and 5. The output is a single line of space-separated strings, where the first string contains characters from even indices, and the second string contains characters from odd indices.

Test Case 1: The even indices are 0 and 2, while the odd indices are 1 and 3. The output follows the same format as Test Case 0.


Code Breakdown:

Reading Input:

#include <cmath>

#include <cstdio>

#include <vector>

#include <iostream>

#include <algorithm>

using namespace std;


int main() {

    int t;

    cin >> t;

    cin.ignore(); // Consume newline


    while (t--) {

        string s;

        getline(cin, s);

        // Code for processing each test case goes here

    }


    return 0;

}

This code reads the number of test cases, t, and then reads each string s for the respective test cases.


Printing Output:

#include <cmath>

#include <cstdio>

#include <vector>

#include <iostream>

#include <algorithm>

using namespace std;


int main() {

    int t;

    cin >> t;

    cin.ignore(); // Consume newline


    while (t--) {

        string s;

        getline(cin, s);


        // Print even-indexed characters

        for (int i = 0; i < s.length(); i += 2) {

            cout << s[i];

        }


        cout << " ";


        // Print odd-indexed characters

        for (int i = 1; i < s.length(); i += 2) {

            cout << s[i];

        }


        cout << endl;

    }


    return 0;

}

Within the loop, this code prints even-indexed characters followed by a space and then prints odd-indexed characters.


Final Code:

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;

int main() {
	int t;
    cin >> t;
    cin.ignore(); // Consume newline

    while (t--) {
    	string s;
        getline(cin, s);

        // Print even-indexed characters
        for (int i = 0; i < s.length(); i += 2) {
        	cout << s[i];
        }

        cout << " ";

        // Print odd-indexed characters
        for (int i = 1; i < s.length(); i += 2) {
        	cout << s[i];
        }

        cout << endl;
        }

        return 0;
}

We hope you enjoy working on Day 6 of the 30 Days of Code challenge! Feel free to explore more challenges and enhance your programming skills.

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